(1/16)^(-x)=8^(3x+1)

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Solution for (1/16)^(-x)=8^(3x+1) equation: 



(1/16)^(-x)=8^(3x+1)

We move all terms to the left:

(1/16)^(-x)-(8^(3x+1))=0



Domain of the equation: 16)^(-x)!=0

x∈R



We add all the numbers together, and all the variables

(+1/16)^(-1x)-(8^(3x+1))=0

We multiply all the terms by the denominator


(+1-((8^(3x+1)))*16)^(-1x)=0



We calculate terms in parentheses: +(+1-((8^(3x+1)))*16)^(-1x), so:

+1-((8^(3x+1)))*16)^(-1x

determiningTheFunctionDomain
-((8^(3x+1)))*16)^(-1x+1

We add all the numbers together, and all the variables

-1x-((8^(3x+1)))*16)^(+1

Back to the equation:

+(-1x-((8^(3x+1)))*16)^(+1)



We add all the numbers together, and all the variables

(-1x-((8^(3x+1)))*16)^1=0

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